Showing posts with label Sum of Large numbers in arrays. Show all posts
Showing posts with label Sum of Large numbers in arrays. Show all posts

Thursday, 12 July 2012

SUM OF LARGE NUMBERS BY USING ARRYS


#include<stdio.h>
#include<conio.h>
#include<string.h>
/* (SUM OF LARGE NUMBERS BY USING ARRYS)*/




void main()
{
char arr1[100], arr2[100];


int f,ans[100]={0,0},x,size1=0,size2=0,value1[100]={0,0},value2[100]={0,0},value3[100]={0,0},cout=0,i=0,sum;


clrscr();


printf("enter your first number");
gets(arr1);


printf("enter your second number");
gets(arr2);
size1=strlen(arr1);

size2=strlen(arr2);

for(x=0;x<size1;x++)
{
value1[x]=arr1[x];
value1[x]=value1[x]-48;
}
for(x=0;x<size2;x++)
{
value2[x]=arr2[x];
value2[x]=value2[x]-48;
}


printf("\n");

for(x=0;x<size1;x++)
{
printf("%d\n",value1[x]);
}
printf("\n\n");

for(x=0;x<size2;x++)
{
printf("%d\n",value2[x]);
}


if(size1>size2)
{
cout=size1;
f=size1-size2;
for(x=0;x<size2;x++)
{
value3[f]=value2[x];
value2[x]=0;
f++;
}
for(x=0;x<size1;x++)
{
value2[x]=value3[x];
}
}


if(size2>size1)
{
cout=size2;
f=size2-size1;
for(x=0;x<size1;x++)
{
value3[f]=value1[x];
value1[x]=0;
f++;
}
for(x=0;x<size2;x++)
{
value1[x]=value3[x];
}
}
if(size1==size2)
{
cout=size1;
}
 clrscr();

printf("\n");

for(x=0;x<cout;x++)
{
printf("%d\t|",value1[x]);

}
printf("\n\n");

for(x=0;x<cout;x++)
{
printf("%d\t|",value2[x]);
}





for (i=cout-1;i>=0;i--)
{
sum=value1[i]+value2[i];
if(sum>=10)
{
ans[i]+=sum%10;
ans[i-1]+=sum/10;
}

if(sum<10)
{
ans[i]=ans[i]+sum;
if(ans[i]>=10)
{
ans[i-1]+=ans[i]/10;
ans[i]=ans[i]%10;
}

}

}



printf("\n\n____________________________________________________  \n\n | ");


for(i=0;i<cout;i++)
{
printf(" %d\t|",ans[i]);
}
getche();

}